What is (y^2-25)/(2y^2-8y-10) ?

The solution to (y^2-25)/(2y^2-8y-10) is (y+5)/(2(y+1))

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simplify (y^2-25)/(2y^2-8y-10)

simplify

\frac{y ^{2} - 25}{2 y ^{2} - 8 y - 10}

\frac{y + 5}{2 ( y + 1 )}

Solution steps

\frac{y ^{2} - 25}{2 y ^{2} - 8 y - 10}

Factor

y^{2} - 25 : (y + 5) (y - 5)

= \frac{( y + 5 ) ( y - 5 )}{2 y ^{2} - 8 y - 10}

Factor

2 y^{2} - 8 y - 10 : 2 (y + 1) (y - 5)

= \frac{( y + 5 ) ( y - 5 )}{2 ( y + 1 ) ( y - 5 )}

Cancel the common factor:

y - 5

= \frac{y + 5}{2 ( y + 1 )}

87 \cdot 614

3 x^{2} (- 10 x^{2} + 10)

100 y^{2} - 49 x^{4}

9 - (- 11)

m^{2} - m - 20

What is (y^2-25)/(2y^2-8y-10) ?
The solution to (y^2-25)/(2y^2-8y-10) is (y+5)/(2(y+1))