What are the solutions to the equation 4x^2+16x+21=0 ?

The solutions to the equation 4x^2+16x+21=0 are x=-2+i(sqrt(5))/2 ,x=-2-i(sqrt(5))/2

Find the zeros of 4x^2+16x+21=0

The zeros of 4x^2+16x+21=0 are x=-2+i(sqrt(5))/2 ,x=-2-i(sqrt(5))/2

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4 x^{2} + 16 x + 21 = 0

x = - 2 + i \frac{5}{2}, x = - 2 - i \frac{5}{2}

Solution steps

4 x^{2} + 16 x + 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 4 \cdot 21}{2 \cdot 4}

Simplify

1 6^{2} - 4 \cdot 4 \cdot 21 : 45 i

x_{1, 2} = \frac{- 16 \pm 4 5 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 16 + 4 5 i}{2 \cdot 4}, x_{2} = \frac{- 16 - 4 5 i}{2 \cdot 4}

x = \frac{- 16 + 4 5 i}{2 \cdot 4} : - 2 + i \frac{5}{2}

x = \frac{- 16 - 4 5 i}{2 \cdot 4} : - 2 - i \frac{5}{2}

The solutions to the quadratic equation are:

x = - 2 + i \frac{5}{2}, x = - 2 - i \frac{5}{2}

\frac{- x + 5}{x - 3} > \frac{3 x}{2 - x}

- 6 u - 36 = - 42

4 (0) - 6 (3) > - 18

a^{2} - x y + a x - a y

x + 19 < 4 x + 4 < 3 x + 14

What are the solutions to the equation 4x^2+16x+21=0 ?
The solutions to the equation 4x^2+16x+21=0 are x=-2+i(sqrt(5))/2 ,x=-2-i(sqrt(5))/2
Find the zeros of 4x^2+16x+21=0
The zeros of 4x^2+16x+21=0 are x=-2+i(sqrt(5))/2 ,x=-2-i(sqrt(5))/2