What is (4^{-1}+4^0)-(9^{-1}+9^0) ?

The solution to (4^{-1}+4^0)-(9^{-1}+9^0) is 5/36

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simplify (4^{-1}+4^0)-(9^{-1}+9^0)

simplify

(4^{- 1} + 4^{0}) - (9^{- 1} + 9^{0})

\frac{5}{36}

Solution steps

(4^{- 1} + 4^{0}) - (9^{- 1} + 9^{0})

Apply rule:

(a) = a

(4^{- 1} + 4^{0}) = 4^{- 1} + 4^{0}

= 4^{- 1} + 4^{0} - (9^{- 1} + 9^{0})

4^{- 1} = \frac{1}{4}

4^{0} = 1

- (9^{- 1} + 9^{0}) = - \frac{10}{9}

= \frac{1}{4} + 1 - \frac{10}{9}

\frac{1}{4} + 1 - \frac{10}{9} = \frac{5}{36}

= \frac{5}{36}

(b^{- 3} c)^{3}

- 12 + (- 7)

- 12 + (- 5)

- \frac{1}{2} x + 3

\frac{7}{6} \div 9

What is (4^{-1}+4^0)-(9^{-1}+9^0) ?
The solution to (4^{-1}+4^0)-(9^{-1}+9^0) is 5/36