What are the solutions to the equation -x^2-9x-20=0 ?

The solutions to the equation -x^2-9x-20=0 are x=-5,x=-4

Find the zeros of -x^2-9x-20=0

The zeros of -x^2-9x-20=0 are x=-5,x=-4

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- x^{2} - 9 x - 20 = 0

x = - 5, x = - 4

Solution steps

- x^{2} - 9 x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 ( - 1 ) ( - 20 )}{2 ( - 1 )}

(- 9)^{2} - 4 (- 1) (- 20) = 1

x_{1, 2} = \frac{- ( - 9 ) \pm 1}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 1}{2 ( - 1 )}, x_{2} = \frac{- ( - 9 ) - 1}{2 ( - 1 )}

x = \frac{- ( - 9 ) + 1}{2 ( - 1 )} : - 5

x = \frac{- ( - 9 ) - 1}{2 ( - 1 )} : - 4

The solutions to the quadratic equation are:

x = - 5, x = - 4

0.86 - 11.8 g = - 2.92 - 12 g

\frac{o - d}{o ^{2} - d ^{2}}

14 ab - 2 a + 21 b - 3

- 171 = 19 v

(x + 5) (x - 4) = x + 5

What are the solutions to the equation -x^2-9x-20=0 ?
The solutions to the equation -x^2-9x-20=0 are x=-5,x=-4
Find the zeros of -x^2-9x-20=0
The zeros of -x^2-9x-20=0 are x=-5,x=-4