What are the solutions to the equation 4v^2-20v=0 ?

The solutions to the equation 4v^2-20v=0 are v=5,v=0

Find the zeros of 4v^2-20v=0

The zeros of 4v^2-20v=0 are v=5,v=0

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4 v^{2} - 20 v = 0

v = 5, v = 0

Solution steps

4 v^{2} - 20 v = 0

Solve with the quadratic formula

v_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 4 \cdot 0}{2 \cdot 4}

(- 20)^{2} - 4 \cdot 4 \cdot 0 = 20

v_{1, 2} = \frac{- ( - 20 ) \pm 20}{2 \cdot 4}

Separate the solutions

v_{1} = \frac{- ( - 20 ) + 20}{2 \cdot 4}, v_{2} = \frac{- ( - 20 ) - 20}{2 \cdot 4}

v = \frac{- ( - 20 ) + 20}{2 \cdot 4} : 5

v = \frac{- ( - 20 ) - 20}{2 \cdot 4} : 0

The solutions to the quadratic equation are:

v = 5, v = 0

\frac{- 8 - 7}{2 - ( - 4 )}

x^{2} - 9 > 0

\frac{5}{6} + \frac{7}{8}

25 - z^{2}

3 \cdot \frac{( - 0.017 5 ^{2} ( - 50 ) ^{3} )}{24 \cdot 2 0 ^{2}}

What are the solutions to the equation 4v^2-20v=0 ?
The solutions to the equation 4v^2-20v=0 are v=5,v=0
Find the zeros of 4v^2-20v=0
The zeros of 4v^2-20v=0 are v=5,v=0