What is (y^2+7y-18)/(y^2-3y+2) ?

The solution to (y^2+7y-18)/(y^2-3y+2) is (y+9)/(y-1)

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simplify (y^2+7y-18)/(y^2-3y+2)

simplify

\frac{y ^{2} + 7 y - 18}{y ^{2} - 3 y + 2}

\frac{y + 9}{y - 1}

Solution steps

\frac{y ^{2} + 7 y - 18}{y ^{2} - 3 y + 2}

Factor

y^{2} + 7 y - 18 : (y - 2) (y + 9)

= \frac{( y - 2 ) ( y + 9 )}{y ^{2} - 3 y + 2}

Factor

y^{2} - 3 y + 2 : (y - 1) (y - 2)

= \frac{( y - 2 ) ( y + 9 )}{( y - 1 ) ( y - 2 )}

Cancel the common factor:

y - 2

= \frac{y + 9}{y - 1}

\frac{3 x ^{3} - 3 x}{x ^{5} - x}

2 i \cdot (- i)

(3 + 2 i) - (4 + 2 i)

\frac{1}{9} - \frac{1}{27}

2 \cdot 33

What is (y^2+7y-18)/(y^2-3y+2) ?
The solution to (y^2+7y-18)/(y^2-3y+2) is (y+9)/(y-1)