What are the solutions to the equation 3x^2+6x=2 ?

The solutions to the equation 3x^2+6x=2 are x=(-3+sqrt(15))/3 ,x=-(3+sqrt(15))/3

Find the zeros of 3x^2+6x=2

The zeros of 3x^2+6x=2 are x=(-3+sqrt(15))/3 ,x=-(3+sqrt(15))/3

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3 x^{2} + 6 x = 2

x = \frac{- 3 + 15}{3}, x = - \frac{3 + 15}{3}

Solution steps

3 x^{2} + 6 x = 2

Move

2

to the left side

3 x^{2} + 6 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 3 ( - 2 )}{2 \cdot 3}

6^{2} - 4 \cdot 3 (- 2) = 215

x_{1, 2} = \frac{- 6 \pm 2 15}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 6 + 2 15}{2 \cdot 3}, x_{2} = \frac{- 6 - 2 15}{2 \cdot 3}

x = \frac{- 6 + 2 15}{2 \cdot 3} : \frac{- 3 + 15}{3}

x = \frac{- 6 - 2 15}{2 \cdot 3} : - \frac{3 + 15}{3}

The solutions to the quadratic equation are:

x = \frac{- 3 + 15}{3}, x = - \frac{3 + 15}{3}

\frac{3 !}{2 ! ( 3 - 2 ) !}

y - 4 = - 2 (- 3 + 3)

4 x^{3} - 6 x^{2 - 28 x}

6 r \cdot 5 r^{2}

x^{2} - 37 x + 322 = 0

What are the solutions to the equation 3x^2+6x=2 ?
The solutions to the equation 3x^2+6x=2 are x=(-3+sqrt(15))/3 ,x=-(3+sqrt(15))/3
Find the zeros of 3x^2+6x=2
The zeros of 3x^2+6x=2 are x=(-3+sqrt(15))/3 ,x=-(3+sqrt(15))/3