What is (2x^4y^7)(4x^3y^{-5}) ?

The solution to (2x^4y^7)(4x^3y^{-5}) is 8x^7y^2

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simplify (2x^4y^7)(4x^3y^{-5})

simplify

(2 x^{4} y^{7}) (4 x^{3} y^{- 5})

8 x^{7} y^{2}

Solution steps

(2 x^{4} y^{7}) (4 x^{3} y^{- 5})

Simplify

4 x^{3} y^{- 5} : \frac{4 x ^{3}}{y ^{5}}

= 2 x^{4} y^{7} \frac{4 x ^{3}}{y ^{5}}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{2 x ^{4} y ^{7} \cdot 4 x ^{3}}{y ^{5}}

Simplify

\frac{y ^{7}}{y ^{5}} : y^{2}

= 2 x^{4} y^{2} \cdot 4 x^{3}

Multiply the numbers:

2 \cdot 4 = 8

= 8 x^{4} y^{2} x^{3}

Simplify

x^{4} x^{3} : x^{7}

= 8 x^{7} y^{2}

4 x^{2} - 9 x^{2}

4 x^{3} - x^{2}

36 y^{2} - x^{6}

(- 4 a^{2} b) (5 a b^{3})

2 p^{2} - 13 p + 20

What is (2x^4y^7)(4x^3y^{-5}) ?
The solution to (2x^4y^7)(4x^3y^{-5}) is 8x^7y^2