What is factor m^4n^4+m^2n^2-132 ?

The solution to factor m^4n^4+m^2n^2-132 is (m^2n^2-11)(m^2n^2+12)

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factor m^4n^4+m^2n^2-132

factor

m^{4} n^{4} + m^{2} n^{2} - 132

(m^{2} n^{2} - 11) (m^{2} n^{2} + 12)

Solution steps

m^{4} n^{4} + m^{2} n^{2} - 132

Break the expression into groups

= (m^{4} n^{4} - 11 m^{2} n^{2}) + (12 m^{2} n^{2} - 132)

Factor out

m^{2} n^{2}

from

m^{4} n^{4} - 11 m^{2} n^{2} : m^{2} n^{2} (m^{2} n^{2} - 11)

Factor out

12

from

12 m^{2} n^{2} - 132 : 12 (m^{2} n^{2} - 11)

= m^{2} n^{2} (m^{2} n^{2} - 11) + 12 (m^{2} n^{2} - 11)

Factor out common term

m^{2} n^{2} - 11

= (m^{2} n^{2} - 11) (m^{2} n^{2} + 12)

(- 3 x^{2} - 3 x - 7) - (x^{2} + 8 x)

e^{\frac{1}{2} l n (1 - x^{2})}

\frac{7}{4} + \frac{8}{3}

sin (x) - sin (x) cos (x)

What is factor m^4n^4+m^2n^2-132 ?
The solution to factor m^4n^4+m^2n^2-132 is (m^2n^2-11)(m^2n^2+12)