What are the solutions to the equation 5x^2-1=0 ?

The solutions to the equation 5x^2-1=0 are x= 1/(sqrt(5)),x=-1/(sqrt(5))

Find the zeros of 5x^2-1=0

The zeros of 5x^2-1=0 are x= 1/(sqrt(5)),x=-1/(sqrt(5))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5 x^{2} - 1 = 0

x = \frac{1}{5}, x = - \frac{1}{5}

Solution steps

5 x^{2} - 1 = 0

Move

1

to the right side

5 x^{2} = 1

Divide both sides by

5

x^{2} = \frac{1}{5}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{1}{5}, x = - \frac{1}{5}

\frac{1}{5} = \frac{1}{5}

- \frac{1}{5} = - \frac{1}{5}

x = \frac{1}{5}, x = - \frac{1}{5}

(6 (x + 1)^{5}) (x - 5)^{2} + (x + 1)^{6} \cdot 2 (x - 5)

\frac{3 x ^{7} y}{27 x ^{7} y ^{7}}

\frac{303}{5} = \frac{5 x}{5}

2.5 (6.25 x + 0.5) = 11

2 x^{2} < 5 x + 12

What are the solutions to the equation 5x^2-1=0 ?
The solutions to the equation 5x^2-1=0 are x= 1/(sqrt(5)),x=-1/(sqrt(5))
Find the zeros of 5x^2-1=0
The zeros of 5x^2-1=0 are x= 1/(sqrt(5)),x=-1/(sqrt(5))