What is factor 2x^3+5x^2-6x-9 ?

The solution to factor 2x^3+5x^2-6x-9 is (x+1)(2x-3)(x+3)

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factor 2x^3+5x^2-6x-9

factor

2 x^{3} + 5 x^{2} - 6 x - 9

(x + 1) (2 x - 3) (x + 3)

Solution steps

2 x^{3} + 5 x^{2} - 6 x - 9

Use the rational root theorem

= (x + 1) \frac{2 x ^{3} + 5 x ^{2} - 6 x - 9}{x + 1}

\frac{2 x ^{3} + 5 x ^{2} - 6 x - 9}{x + 1} = 2 x^{2} + 3 x - 9

= (x + 1) (2 x^{2} + 3 x - 9)

Factor

2 x^{2} + 3 x - 9 : (2 x - 3) (x + 3)

= (x + 1) (2 x - 3) (x + 3)

- 2 (- 2 x^{2} - 9 x)

4 x^{3} \cdot 2 x

\frac{3}{8} - \frac{5}{6}

lo g_{1.5} (\frac{4}{9})

\frac{58}{4}

What is factor 2x^3+5x^2-6x-9 ?
The solution to factor 2x^3+5x^2-6x-9 is (x+1)(2x-3)(x+3)