What is (z^2-4)/(z^2+z-6) ?

The solution to (z^2-4)/(z^2+z-6) is (z+2)/(z+3)

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simplify (z^2-4)/(z^2+z-6)

simplify

\frac{z ^{2} - 4}{z ^{2} + z - 6}

\frac{z + 2}{z + 3}

Solution steps

\frac{z ^{2} - 4}{z ^{2} + z - 6}

Factor

z^{2} - 4 : (z + 2) (z - 2)

= \frac{( z + 2 ) ( z - 2 )}{z ^{2} + z - 6}

Factor

z^{2} + z - 6 : (z - 2) (z + 3)

= \frac{( z + 2 ) ( z - 2 )}{( z - 2 ) ( z + 3 )}

Cancel the common factor:

z - 2

= \frac{z + 2}{z + 3}

81 - 4 y^{2}

(6 c + 7) (6 c - 7)

(w + 6) (w - 6)

\frac{b ^{2} + 3 b - 4}{b ^{2} + 9 b + 20}

\frac{3 ^{- 3}}{6 ^{- 2}}