What is (a^{-2}+a^{-3})^{-1} ?

The solution to (a^{-2}+a^{-3})^{-1} is (a^3)/(a+1)

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simplify (a^{-2}+a^{-3})^{-1}

simplify

(a^{- 2} + a^{- 3})^{- 1}

\frac{a ^{3}}{a + 1}

Solution steps

(a^{- 2} + a^{- 3})^{- 1}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

(a^{- 2} + a^{- 3})^{- 1} = \frac{1}{a ^{- 2} + a ^{- 3}}

= \frac{1}{a ^{- 2} + a ^{- 3}}

Simplify

a^{- 2} + a^{- 3} : \frac{1}{a ^{2}} + \frac{1}{a ^{3}}

= \frac{1}{\frac{1}{a ^{2}} + \frac{1}{a ^{3}}}

Join

\frac{1}{a ^{2}} + \frac{1}{a ^{3}} : \frac{a + 1}{a ^{3}}

= \frac{1}{\frac{a + 1}{a ^{3}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{a ^{3}}{a + 1}

\frac{a ^{2} + ab}{a ^{2} - b ^{2}}

e^{l n (1 + x^{2})}

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100 + 300

2 y - 10 y

What is (a^{-2}+a^{-3})^{-1} ?
The solution to (a^{-2}+a^{-3})^{-1} is (a^3)/(a+1)