What is factor 81u^4-1 ?

The solution to factor 81u^4-1 is (9u^2+1)(3u+1)(3u-1)

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factor 81u^4-1

factor

81 u^{4} - 1

(9 u^{2} + 1) (3 u + 1) (3 u - 1)

Solution steps

81 u^{4} - 1

Apply exponent rules

= (9 u^{2})^{2} - 1^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(9 u^{2})^{2} - 1^{2} = (9 u^{2} + 1) (9 u^{2} - 1)

= (9 u^{2} + 1) (9 u^{2} - 1)

Factor

9 u^{2} - 1 : (3 u + 1) (3 u - 1)

= (9 u^{2} + 1) (3 u + 1) (3 u - 1)

3 x \cdot 7

lo g_{2} (64)

- 20 + 6

- (20 + d)

\frac{9}{8} \div \frac{5}{8}