What are the solutions to the equation x^2+3/4 x=-1/4 ?

The solutions to the equation x^2+3/4 x=-1/4 are x=-3/8+i(sqrt(7))/8 ,x=-3/8-i(sqrt(7))/8

Find the zeros of x^2+3/4 x=-1/4

The zeros of x^2+3/4 x=-1/4 are x=-3/8+i(sqrt(7))/8 ,x=-3/8-i(sqrt(7))/8

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x^{2} + \frac{3}{4} x = - \frac{1}{4}

x = - \frac{3}{8} + i \frac{7}{8}, x = - \frac{3}{8} - i \frac{7}{8}

Solution steps

x^{2} + \frac{3}{4} x = - \frac{1}{4}

Multiply both sides by

4

4 x^{2} + 3 x = - 1

Move

1

to the left side

4 x^{2} + 3 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

Simplify

3^{2} - 4 \cdot 4 \cdot 1 : 7 i

x_{1, 2} = \frac{- 3 \pm 7 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 3 + 7 i}{2 \cdot 4}, x_{2} = \frac{- 3 - 7 i}{2 \cdot 4}

x = \frac{- 3 + 7 i}{2 \cdot 4} : - \frac{3}{8} + i \frac{7}{8}

x = \frac{- 3 - 7 i}{2 \cdot 4} : - \frac{3}{8} - i \frac{7}{8}

The solutions to the quadratic equation are:

x = - \frac{3}{8} + i \frac{7}{8}, x = - \frac{3}{8} - i \frac{7}{8}

x^{2} - x - 4 = 2

3.1 x - 1.4 \leq 1.3 x + 6.7

x^{2} - 64 y^{2}

7 x = 4 x

4 r - 7 s

What are the solutions to the equation x^2+3/4 x=-1/4 ?
The solutions to the equation x^2+3/4 x=-1/4 are x=-3/8+i(sqrt(7))/8 ,x=-3/8-i(sqrt(7))/8
Find the zeros of x^2+3/4 x=-1/4
The zeros of x^2+3/4 x=-1/4 are x=-3/8+i(sqrt(7))/8 ,x=-3/8-i(sqrt(7))/8