What is (2w^2+w-5)+(4w^2+7w+1) ?

The solution to (2w^2+w-5)+(4w^2+7w+1) is 6w^2+8w-4

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simplify (2w^2+w-5)+(4w^2+7w+1)

simplify

(2 w^{2} + w - 5) + (4 w^{2} + 7 w + 1)

6 w^{2} + 8 w - 4

Solution steps

(2 w^{2} + w - 5) + (4 w^{2} + 7 w + 1)

Simplify

(2 w^{2} + w - 5) + (4 w^{2} + 7 w + 1) : 2 w^{2} + w - 5 + 4 w^{2} + 7 w + 1

= 2 w^{2} + w - 5 + 4 w^{2} + 7 w + 1

Group like terms

= 2 w^{2} + 4 w^{2} + w + 7 w - 5 + 1

Add similar elements:

2 w^{2} + 4 w^{2} = 6 w^{2}

= 6 w^{2} + w + 7 w - 5 + 1

Add similar elements:

w + 7 w = 8 w

= 6 w^{2} + 8 w - 5 + 1

Add the numbers:

- 5 + 1 = - 4

= 6 w^{2} + 8 w - 4

- 2 (3 + m)

10 + 6

18 - 7

19 - 7

- 3 \cdot (- 12)

What is (2w^2+w-5)+(4w^2+7w+1) ?
The solution to (2w^2+w-5)+(4w^2+7w+1) is 6w^2+8w-4