What are the solutions to the equation y^2+5y+3=0 ?

The solutions to the equation y^2+5y+3=0 are y=(-5+sqrt(13))/2 ,y=(-5-sqrt(13))/2

Find the zeros of y^2+5y+3=0

The zeros of y^2+5y+3=0 are y=(-5+sqrt(13))/2 ,y=(-5-sqrt(13))/2

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y^{2} + 5 y + 3 = 0

y = \frac{- 5 + 13}{2}, y = \frac{- 5 - 13}{2}

Decimal Notation

y = - 0.69722 \dots, y = - 4.30277 \dots

Solution steps

y^{2} + 5 y + 3 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot 3 = 13

y_{1, 2} = \frac{- 5 \pm 13}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 5 + 13}{2 \cdot 1}, y_{2} = \frac{- 5 - 13}{2 \cdot 1}

y = \frac{- 5 + 13}{2 \cdot 1} : \frac{- 5 + 13}{2}

y = \frac{- 5 - 13}{2 \cdot 1} : \frac{- 5 - 13}{2}

The solutions to the quadratic equation are:

y = \frac{- 5 + 13}{2}, y = \frac{- 5 - 13}{2}

2 + x = 0

4 x + 25 = 9 x

- \frac{8}{3} - 4

x^{2} + 16

\frac{1}{7}

What are the solutions to the equation y^2+5y+3=0 ?
The solutions to the equation y^2+5y+3=0 are y=(-5+sqrt(13))/2 ,y=(-5-sqrt(13))/2
Find the zeros of y^2+5y+3=0
The zeros of y^2+5y+3=0 are y=(-5+sqrt(13))/2 ,y=(-5-sqrt(13))/2