What is ((3+4i)(1-2i))/(1+i) ?

The solution to ((3+4i)(1-2i))/(1+i) is 9/2-13/2 i

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simplify ((3+4i)(1-2i))/(1+i)

simplify

\frac{( 3 + 4 i ) ( 1 - 2 i )}{1 + i}

\frac{9}{2} - \frac{13}{2} i

Solution steps

\frac{( 3 + 4 i ) ( 1 - 2 i )}{1 + i}

Multiply by the conjugate

\frac{1 - i}{1 - i}

= \frac{( 3 + 4 i ) ( 1 - 2 i ) ( 1 - i )}{( 1 + i ) ( 1 - i )}

Simplify

\frac{( 3 + 4 i ) ( 1 - 2 i ) ( 1 - i )}{( 1 + i ) ( 1 - i )} : \frac{9 - 13 i}{2}

= \frac{9 - 13 i}{2}

Rewrite in standard complex form:

\frac{9}{2} - \frac{13}{2} i

= \frac{9}{2} - \frac{13}{2} i

(2 a + 1)^{3} - 2 (2 a + 1)^{2} + 20

lo g_{10} (2) (32)

\frac{1}{5 + 3 i}

1 - (- 10)

2 x^{11}

What is ((3+4i)(1-2i))/(1+i) ?
The solution to ((3+4i)(1-2i))/(1+i) is 9/2-13/2 i