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Popular >

|4x-5|<= 12

Solution

∣ 4 x - 5 ∣ \leq 12

Solution

- \frac{7}{4} \leq x \leq \frac{17}{4}

+2

Solution steps

∣ 4 x - 5 ∣ \leq 12

Apply absolute rule: If

∣ u ∣ \leq a, a > 0

then

- a \leq u \leq a

- 12 \leq 4 x - 5 \leq 12

4 x - 5 \geq - 12 and 4 x - 5 \leq 12

x \geq - \frac{7}{4} and x \leq \frac{17}{4}

Merge Overlapping Intervals

- \frac{7}{4} \leq x \leq \frac{17}{4}

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∣ x + 1 ∣ + ∣ x - 2 ∣ \leq 4

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Frequently Asked Questions (FAQ)

What is |4x-5|<= 12 ?
The solution to |4x-5|<= 12 is -7/4 <= x<= 17/4