What is (n^3c^{-2})^{-2} ?

The solution to (n^3c^{-2})^{-2} is (c^4)/(n^6)

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simplify (n^3c^{-2})^{-2}

simplify

(n^{3} c^{- 2})^{- 2}

\frac{c ^{4}}{n ^{6}}

Solution steps

(n^{3} c^{- 2})^{- 2}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(n^{3} c^{- 2})^{- 2} = \frac{1}{( n ^{3} c ^{- 2} ) ^{2}}

= \frac{1}{( n ^{3} c ^{- 2} ) ^{2}}

Simplify

(n^{3} c^{- 2})^{2} : \frac{n ^{6}}{c ^{4}}

= \frac{1}{\frac{n ^{6}}{c ^{4}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{c ^{4}}{n ^{6}}

\frac{1}{5} + \frac{2}{10}

(a - b)^{2} + 5 (a - b) - 24

(1 + x)^{12}

80 a^{2} b^{3} c^{3}

\frac{b}{a} - \frac{a}{b}