What is (x^2-9)/(2x^2+7x+3) ?

The solution to (x^2-9)/(2x^2+7x+3) is (x-3)/(2x+1)

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simplify (x^2-9)/(2x^2+7x+3)

simplify

\frac{x ^{2} - 9}{2 x ^{2} + 7 x + 3}

\frac{x - 3}{2 x + 1}

Solution steps

\frac{x ^{2} - 9}{2 x ^{2} + 7 x + 3}

Factor

x^{2} - 9 : (x + 3) (x - 3)

= \frac{( x + 3 ) ( x - 3 )}{2 x ^{2} + 7 x + 3}

Factor

2 x^{2} + 7 x + 3 : (2 x + 1) (x + 3)

= \frac{( x + 3 ) ( x - 3 )}{( 2 x + 1 ) ( x + 3 )}

Cancel the common factor:

x + 3

= \frac{x - 3}{2 x + 1}

(- x - 4)^{2}

(32 x^{10})^{\frac{3}{5}}

(h - 1)^{2}

h (1)

What is (x^2-9)/(2x^2+7x+3) ?
The solution to (x^2-9)/(2x^2+7x+3) is (x-3)/(2x+1)