What is (2x^{-4})^{-3}x^{-3} ?

The solution to (2x^{-4})^{-3}x^{-3} is (x^9)/8

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simplify (2x^{-4})^{-3}x^{-3}

simplify

(2 x^{- 4})^{- 3} x^{- 3}

\frac{x ^{9}}{8}

Solution steps

(2 x^{- 4})^{- 3} x^{- 3}

Simplify

(2 x^{- 4})^{- 3} : \frac{x ^{12}}{8}

= \frac{x ^{12}}{8} x^{- 3}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

x^{- 3} = \frac{1}{x ^{3}}

= \frac{x ^{12}}{8} \cdot \frac{1}{x ^{3}}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{x ^{12} \cdot 1}{8 x ^{3}}

Apply rule:

a \cdot 1 = a

x^{12} \cdot 1 = x^{12}

= \frac{x ^{12}}{8 x ^{3}}

Simplify

\frac{x ^{12}}{x ^{3}} : x^{9}

= \frac{x ^{9}}{8}

(2 x^{3} + 9 x - 8) - (4 x^{2} - 15 x + 7)

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