What is sqrt(12x^2y^{-4)} ?

The solution to sqrt(12x^2y^{-4)} is (2sqrt(3)x)/(y^2)

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simplify sqrt(12x^2y^{-4)}

simplify

12 x^{2} y^{- 4}

\frac{2 3 x}{y ^{2}}

Solution steps

12 x^{2} y^{- 4}

12 x^{2} y^{- 4} = 12 x^{2} y^{- 4}

= 12 x^{2} y^{- 4}

Apply radical rule:

a^{2} = a,

assuming

a \geq 0

x^{2} = x

= 12 x y^{- 4}

12 = 23

= 23 x y^{- 4}

Simplify

y^{- 4} : \frac{1}{y ^{2}}

= 23 x \frac{1}{y ^{2}}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{2 3 x \cdot 1}{y ^{2}}

Multiply the numbers:

2 \cdot 1 = 2

= \frac{2 3 x}{y ^{2}}

4 a^{2} b^{0} \cdot 4 a b^{2}

72 x^{3} y^{4} z^{5}

6 + 2 (7 x - 3)

- 4 (- 8)

(c + 7)^{2}

What is sqrt(12x^2y^{-4)} ?
The solution to sqrt(12x^2y^{-4)} is (2sqrt(3)x)/(y^2)