What are the solutions to the equation x^2-10x+21=0 ?

The solutions to the equation x^2-10x+21=0 are x=7,x=3

Find the zeros of x^2-10x+21=0

The zeros of x^2-10x+21=0 are x=7,x=3

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x^{2} - 10 x + 21 = 0

x = 7, x = 3

Solution steps

x^{2} - 10 x + 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 21}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 21 = 4

x_{1, 2} = \frac{- ( - 10 ) \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 4}{2 \cdot 1}, x_{2} = \frac{- ( - 10 ) - 4}{2 \cdot 1}

x = \frac{- ( - 10 ) + 4}{2 \cdot 1} : 7

x = \frac{- ( - 10 ) - 4}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

x = 7, x = 3

\frac{3}{4} + \frac{1}{5}

2175

(x - 4)^{2} = 10

8 x - 20 = 52

lo g_{e} (0.5)

What are the solutions to the equation x^2-10x+21=0 ?
The solutions to the equation x^2-10x+21=0 are x=7,x=3
Find the zeros of x^2-10x+21=0
The zeros of x^2-10x+21=0 are x=7,x=3