What are the solutions to the equation x^2=7-x ?

The solutions to the equation x^2=7-x are x=(-1+sqrt(29))/2 ,x=(-1-sqrt(29))/2

Find the zeros of x^2=7-x

The zeros of x^2=7-x are x=(-1+sqrt(29))/2 ,x=(-1-sqrt(29))/2

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x^{2} = 7 - x

x = \frac{- 1 + 29}{2}, x = \frac{- 1 - 29}{2}

Decimal Notation

x = 2.19258 \dots, x = - 3.19258 \dots

Solution steps

x^{2} = 7 - x

Move

x

to the left side

x^{2} + x = 7

Move

7

to the left side

x^{2} + x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 7 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 7) = 29

x_{1, 2} = \frac{- 1 \pm 29}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 29}{2 \cdot 1}, x_{2} = \frac{- 1 - 29}{2 \cdot 1}

x = \frac{- 1 + 29}{2 \cdot 1} : \frac{- 1 + 29}{2}

x = \frac{- 1 - 29}{2 \cdot 1} : \frac{- 1 - 29}{2}

The solutions to the quadratic equation are:

x = \frac{- 1 + 29}{2}, x = \frac{- 1 - 29}{2}

x^{3} - 3 x^{2} - 2 x

\frac{3}{5} - \frac{5}{6}

0.002 \cdot 0.001 = 0.05 \cdot x

29 = 5 x - 1

\frac{5}{2} - \frac{3}{5}

What are the solutions to the equation x^2=7-x ?
The solutions to the equation x^2=7-x are x=(-1+sqrt(29))/2 ,x=(-1-sqrt(29))/2
Find the zeros of x^2=7-x
The zeros of x^2=7-x are x=(-1+sqrt(29))/2 ,x=(-1-sqrt(29))/2