What are the solutions to the equation 3x^2-36x+96=0 ?

The solutions to the equation 3x^2-36x+96=0 are x=8,x=4

Find the zeros of 3x^2-36x+96=0

The zeros of 3x^2-36x+96=0 are x=8,x=4

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3 x^{2} - 36 x + 96 = 0

x = 8, x = 4

Solution steps

3 x^{2} - 36 x + 96 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 36 ) \pm ( - 36 ) ^{2} - 4 \cdot 3 \cdot 96}{2 \cdot 3}

(- 36)^{2} - 4 \cdot 3 \cdot 96 = 12

x_{1, 2} = \frac{- ( - 36 ) \pm 12}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 36 ) + 12}{2 \cdot 3}, x_{2} = \frac{- ( - 36 ) - 12}{2 \cdot 3}

x = \frac{- ( - 36 ) + 12}{2 \cdot 3} : 8

x = \frac{- ( - 36 ) - 12}{2 \cdot 3} : 4

The solutions to the quadratic equation are:

x = 8, x = 4

4 + 4 a

- 1 < \frac{5}{9} x + \frac{2}{3} \leq \frac{11}{9}

- x^{2} + x + 2

(5 - \frac{9}{2})^{2}

(x + 3) (x - 1) (x - 6) \leq 0

What are the solutions to the equation 3x^2-36x+96=0 ?
The solutions to the equation 3x^2-36x+96=0 are x=8,x=4
Find the zeros of 3x^2-36x+96=0
The zeros of 3x^2-36x+96=0 are x=8,x=4