What is (2x^{-2})^{-4}x^{-4} ?

The solution to (2x^{-2})^{-4}x^{-4} is (x^4)/(16)

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simplify (2x^{-2})^{-4}x^{-4}

simplify

(2 x^{- 2})^{- 4} x^{- 4}

\frac{x ^{4}}{16}

Solution steps

(2 x^{- 2})^{- 4} x^{- 4}

Simplify

(2 x^{- 2})^{- 4} : \frac{x ^{8}}{16}

= \frac{x ^{8}}{16} x^{- 4}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

x^{- 4} = \frac{1}{x ^{4}}

= \frac{x ^{8}}{16} \cdot \frac{1}{x ^{4}}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{x ^{8} \cdot 1}{16 x ^{4}}

Apply rule:

a \cdot 1 = a

x^{8} \cdot 1 = x^{8}

= \frac{x ^{8}}{16 x ^{4}}

Simplify

\frac{x ^{8}}{x ^{4}} : x^{4}

= \frac{x ^{4}}{16}

(- 6) + 4

e^{i \cdot 0}

\frac{x ^{2} - 2 x - 15}{x - 5}

(- 6 + - 9)^{2}

(- 7) + 9

What is (2x^{-2})^{-4}x^{-4} ?
The solution to (2x^{-2})^{-4}x^{-4} is (x^4)/(16)