What is expand (3x^4-2y^3)^3 ?

The solution to expand (3x^4-2y^3)^3 is 27x^{12}-54x^8y^3+36x^4y^6-8y^9

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expand (3x^4-2y^3)^3

expand

(3 x^{4} - 2 y^{3})^{3}

27 x^{12} - 54 x^{8} y^{3} + 36 x^{4} y^{6} - 8 y^{9}

Solution steps

(3 x^{4} - 2 y^{3})^{3}

Apply Perfect Cube Formula:

(a - b)^{3} = a^{3} - 3 a^{2} b + 3 a b^{2} - b^{3}

(3 x^{4} - 2 y^{3})^{3} = (3 x^{4})^{3} - 3 (3 x^{4})^{2} \cdot 2 y^{3} + 3 \cdot 3 x^{4} (2 y^{3})^{2} - (2 y^{3})^{3}

= (3 x^{4})^{3} - 3 (3 x^{4})^{2} \cdot 2 y^{3} + 3 \cdot 3 x^{4} (2 y^{3})^{2} - (2 y^{3})^{3}

Simplify

(3 x^{4})^{3} - 3 (3 x^{4})^{2} \cdot 2 y^{3} + 3 \cdot 3 x^{4} (2 y^{3})^{2} - (2 y^{3})^{3} : 27 x^{12} - 54 x^{8} y^{3} + 36 x^{4} y^{6} - 8 y^{9}

= 27 x^{12} - 54 x^{8} y^{3} + 36 x^{4} y^{6} - 8 y^{9}

(a^{2} + 5 a + 4)^{2}

2 x - 4 y + 6 + 3 x - 9 y - 4

\frac{1}{x + y + 3} - \frac{1}{x + 3}

\frac{1}{3} \cdot x

[(- 2)^{2}]^{4}

What is expand (3x^4-2y^3)^3 ?
The solution to expand (3x^4-2y^3)^3 is 27x^{12}-54x^8y^3+36x^4y^6-8y^9