What is factor 125x^9-27y^6 ?

The solution to factor 125x^9-27y^6 is (5x^3-3y^2)(25x^6+15x^3y^2+9y^4)

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factor 125x^9-27y^6

factor

125 x^{9} - 27 y^{6}

(5 x^{3} - 3 y^{2}) (25 x^{6} + 15 x^{3} y^{2} + 9 y^{4})

Solution steps

125 x^{9} - 27 y^{6}

Apply exponent rules

= (5 x^{3})^{3} - (3 y^{2})^{3}

Apply Difference of Cubes Formula:

x^{3} - y^{3} = (x - y) (x^{2} + x y + y^{2})

(5 x^{3})^{3} - (3 y^{2})^{3} = (5 x^{3} - 3 y^{2}) ((5 x^{3})^{2} + 5 x^{3} \cdot 3 y^{2} + (3 y^{2})^{2})

= (5 x^{3} - 3 y^{2}) ((5 x^{3})^{2} + 5 x^{3} \cdot 3 y^{2} + (3 y^{2})^{2})

Simplify

(5 x^{3})^{2} + 5 x^{3} \cdot 3 y^{2} + (3 y^{2})^{2} : 25 x^{6} + 15 x^{3} y^{2} + 9 y^{4}

= (5 x^{3} - 3 y^{2}) (25 x^{6} + 15 x^{3} y^{2} + 9 y^{4})

- 40 (\frac{2 ( 10 b + 23 )}{25}) + 48 b = 17.2

- 5 < \frac{z}{- 1} - 8

2 - (- \frac{3}{4})^{2}

9 r^{3} s^{2} - 30 r s^{3}

\frac{1}{16} \cdot 4

What is factor 125x^9-27y^6 ?
The solution to factor 125x^9-27y^6 is (5x^3-3y^2)(25x^6+15x^3y^2+9y^4)