What is (2s+3i-4m)+(3s-2i+3m) ?

The solution to (2s+3i-4m)+(3s-2i+3m) is (5s-m)+i

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simplify (2s+3i-4m)+(3s-2i+3m)

simplify

(2 s + 3 i - 4 m) + (3 s - 2 i + 3 m)

(5 s - m) + i

Solution steps

(2 s + 3 i - 4 m) + (3 s - 2 i + 3 m)

Rewrite

2 s + 3 i - 4 m

in standard complex form:

(2 s - 4 m) + 3 i

Rewrite

3 s - 2 i + 3 m

in standard complex form:

(3 s + 3 m) - 2 i

= (2 s - 4 m) + 3 i + (3 s + 3 m) - 2 i

Group the real part and the imaginary part of the complex number

(a + bi) + (c + d i) = (a + c) + (b + d) i

= ((2 s - 4 m) + (3 s + 3 m)) + (3 - 2) i

Simplify

((2 s - 4 m) + (3 s + 3 m)) + (3 - 2) i : 5 s - m + i

= 5 s - m + i

4 x^{4}

(24 - i) (\frac{4}{5} - 2 i)

6 \frac{6}{10} - 3 \frac{7}{10}

1 0^{6} \cdot 1 0^{3}

What is (2s+3i-4m)+(3s-2i+3m) ?
The solution to (2s+3i-4m)+(3s-2i+3m) is (5s-m)+i