What is expand (3x^2-2x-4)(2x^2-x+2) ?

The solution to expand (3x^2-2x-4)(2x^2-x+2) is 6x^4-7x^3-8

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expand (3x^2-2x-4)(2x^2-x+2)

expand

(3 x^{2} - 2 x - 4) (2 x^{2} - x + 2)

6 x^{4} - 7 x^{3} - 8

Solution steps

(3 x^{2} - 2 x - 4) (2 x^{2} - x + 2)

Distribute parentheses

= 3 x^{2} \cdot 2 x^{2} + 3 x^{2} (- x) + 3 x^{2} \cdot 2 - 2 x \cdot 2 x^{2} - 2 x (- x) - 2 x \cdot 2 - 4 \cdot 2 x^{2} - 4 (- x) - 4 \cdot 2

Simplify

3 x^{2} \cdot 2 x^{2} + 3 x^{2} (- x) + 3 x^{2} \cdot 2 - 2 x \cdot 2 x^{2} - 2 x (- x) - 2 x \cdot 2 - 4 \cdot 2 x^{2} - 4 (- x) - 4 \cdot 2 : 6 x^{4} - 7 x^{3} - 8

= 6 x^{4} - 7 x^{3} - 8

(- 5 c^{- 3})^{4}

5 x^{2} + 22 x - 15

315.12 + (- 142.26)

20 y^{4} - 45 y^{2}

16 x^{4} + 32 x^{3} - 24 x^{2}

What is expand (3x^2-2x-4)(2x^2-x+2) ?
The solution to expand (3x^2-2x-4)(2x^2-x+2) is 6x^4-7x^3-8