What is ((2x^2)/y)^{-2} ?

The solution to ((2x^2)/y)^{-2} is (y^2)/(4x^4)

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simplify ((2x^2)/y)^{-2}

simplify

(\frac{2 x ^{2}}{y})^{- 2}

\frac{y ^{2}}{4 x ^{4}}

Solution steps

(\frac{2 x ^{2}}{y})^{- 2}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(\frac{2 x ^{2}}{y})^{- 2} = \frac{1}{( \frac{2 x ^{2}}{y} ) ^{2}}

= \frac{1}{( \frac{2 x ^{2}}{y} ) ^{2}}

Simplify

(\frac{2 x ^{2}}{y})^{2} : \frac{4 x ^{4}}{y ^{2}}

= \frac{1}{\frac{4 x ^{4}}{y ^{2}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{y ^{2}}{4 x ^{4}}

\frac{e ^{4 i} - e ^{- 4 i}}{2 i}

\frac{9}{4} + \frac{1}{2}

(5^{2})^{0}

e^{l n ∣ x ∣ + x}

\frac{e}{e}