What is expand (x^2-x+4)(3x^2+3x-4) ?

The solution to expand (x^2-x+4)(3x^2+3x-4) is 3x^4+5x^2+16x-16

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (x^2-x+4)(3x^2+3x-4)

expand

(x^{2} - x + 4) (3 x^{2} + 3 x - 4)

3 x^{4} + 5 x^{2} + 16 x - 16

Solution steps

(x^{2} - x + 4) (3 x^{2} + 3 x - 4)

Distribute parentheses

= x^{2} \cdot 3 x^{2} + x^{2} \cdot 3 x + x^{2} (- 4) - x \cdot 3 x^{2} - x \cdot 3 x - x (- 4) + 4 \cdot 3 x^{2} + 4 \cdot 3 x + 4 (- 4)

Simplify

x^{2} \cdot 3 x^{2} + x^{2} \cdot 3 x + x^{2} (- 4) - x \cdot 3 x^{2} - x \cdot 3 x - x (- 4) + 4 \cdot 3 x^{2} + 4 \cdot 3 x + 4 (- 4) : 3 x^{4} + 5 x^{2} + 16 x - 16

= 3 x^{4} + 5 x^{2} + 16 x - 16

(z + 5) (z - 5)

(\frac{a ^{2 x}}{b ^{y}})^{3 x}

17 v^{2} - 68

∣ 4 + 3 i ∣

(x + a) (y + a) (z + a)

What is expand (x^2-x+4)(3x^2+3x-4) ?
The solution to expand (x^2-x+4)(3x^2+3x-4) is 3x^4+5x^2+16x-16