What is \sqrt[4]{(3x^5y^{-2})^4} ?

The solution to \sqrt[4]{(3x^5y^{-2})^4} is (3x^5)/(y^2)

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simplify \sqrt[4]{(3x^5y^{-2})^4}

simplify

\frac{3 x ^{5}}{y ^{2}}

Solution steps

Apply radical rule:

assuming

a \geq 0

= 3 x^{5} y^{- 2}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

y^{- 2} = \frac{1}{y ^{2}}

= 3 x^{5} \frac{1}{y ^{2}}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{3 x ^{5} \cdot 1}{y ^{2}}

Multiply the numbers:

3 \cdot 1 = 3

= \frac{3 x ^{5}}{y ^{2}}

\frac{1 + i}{4 - 3 i}

(y + x)^{2}

- 3 (x - 4) + 3 (a - 6)

6 \cdot 975

2 x (3 x)

What is \sqrt[4]{(3x^5y^{-2})^4} ?
The solution to \sqrt[4]{(3x^5y^{-2})^4} is (3x^5)/(y^2)