What are the solutions to the equation 9x^2-12x+148=0 ?

The solutions to the equation 9x^2-12x+148=0 are x= 2/3+4i,x= 2/3-4i

Find the zeros of 9x^2-12x+148=0

The zeros of 9x^2-12x+148=0 are x= 2/3+4i,x= 2/3-4i

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9 x^{2} - 12 x + 148 = 0

x = \frac{2}{3} + 4 i, x = \frac{2}{3} - 4 i

Solution steps

9 x^{2} - 12 x + 148 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 9 \cdot 148}{2 \cdot 9}

Simplify

(- 12)^{2} - 4 \cdot 9 \cdot 148 : 72 i

x_{1, 2} = \frac{- ( - 12 ) \pm 72 i}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 72 i}{2 \cdot 9}, x_{2} = \frac{- ( - 12 ) - 72 i}{2 \cdot 9}

x = \frac{- ( - 12 ) + 72 i}{2 \cdot 9} : \frac{2}{3} + 4 i

x = \frac{- ( - 12 ) - 72 i}{2 \cdot 9} : \frac{2}{3} - 4 i

The solutions to the quadratic equation are:

x = \frac{2}{3} + 4 i, x = \frac{2}{3} - 4 i

\frac{4}{3}

m^{2} = 16

\frac{x}{x - 1} > 0

∣ - 4 x - 3 ∣ \leq = 8

(\frac{5}{6})^{10}

What are the solutions to the equation 9x^2-12x+148=0 ?
The solutions to the equation 9x^2-12x+148=0 are x= 2/3+4i,x= 2/3-4i
Find the zeros of 9x^2-12x+148=0
The zeros of 9x^2-12x+148=0 are x= 2/3+4i,x= 2/3-4i