What is (2x^2+7)-(-2x^2-2x-7) ?

The solution to (2x^2+7)-(-2x^2-2x-7) is 4x^2+2x+14

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simplify (2x^2+7)-(-2x^2-2x-7)

simplify

(2 x^{2} + 7) - (- 2 x^{2} - 2 x - 7)

4 x^{2} + 2 x + 14

Solution steps

(2 x^{2} + 7) - (- 2 x^{2} - 2 x - 7)

Apply rule:

(a) = a

(2 x^{2} + 7) = 2 x^{2} + 7

= 2 x^{2} + 7 - (- 2 x^{2} - 2 x - 7)

Apply the distributive law:

- (- a - b) = a + b

- (- 2 x^{2} - 2 x - 7) = 2 x^{2} + 2 x + 7

= 2 x^{2} + 7 + 2 x^{2} + 2 x + 7

Group like terms

= 2 x^{2} + 2 x^{2} + 2 x + 7 + 7

Add similar elements:

2 x^{2} + 2 x^{2} = 4 x^{2}

= 4 x^{2} + 2 x + 7 + 7

Add the numbers:

7 + 7 = 14

= 4 x^{2} + 2 x + 14

\frac{x - 3}{5 x} + \frac{1}{x + 2}

\frac{e ^{- 0.01} - 1}{- 0.01}

(2 a + 3 b - 4 c)^{2}

180 x^{8} y^{19}

\frac{37}{24}

What is (2x^2+7)-(-2x^2-2x-7) ?
The solution to (2x^2+7)-(-2x^2-2x-7) is 4x^2+2x+14