What is log_{2}(128)-log_{2}(16) ?

The solution to log_{2}(128)-log_{2}(16) is 3

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simplify log_{2}(128)-log_{2}(16)

simplify

lo g_{2} (128) - lo g_{2} (16)

3

Solution steps

lo g_{2} (128) - lo g_{2} (16)

lo g_{2} (128) = 7

lo g_{2} (16) = 4

= 7 - 4

Subtract the numbers:

7 - 4 = 3

= 3

\frac{5}{6} + \frac{1}{5}

x^{2} - \frac{1}{2} x

x 125 x - 9 80 x^{3}

(3 x - 2 y - z) (3 x - 2 y + z)

What is log_{2}(128)-log_{2}(16) ?
The solution to log_{2}(128)-log_{2}(16) is 3