What is (3x^2-2)(2x+4)-2x^2+6x+7 ?

The solution to (3x^2-2)(2x+4)-2x^2+6x+7 is 6x^3+10x^2+2x-1

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simplify (3x^2-2)(2x+4)-2x^2+6x+7

simplify

(3 x^{2} - 2) (2 x + 4) - 2 x^{2} + 6 x + 7

6 x^{3} + 10 x^{2} + 2 x - 1

Solution steps

(3 x^{2} - 2) (2 x + 4) - 2 x^{2} + 6 x + 7

Expand

(3 x^{2} - 2) (2 x + 4) : 6 x^{3} + 12 x^{2} - 4 x - 8

= 6 x^{3} + 12 x^{2} - 4 x - 8 - 2 x^{2} + 6 x + 7

Group like terms

= 6 x^{3} + 12 x^{2} - 2 x^{2} - 4 x + 6 x - 8 + 7

Add similar elements:

12 x^{2} - 2 x^{2} = 10 x^{2}

= 6 x^{3} + 10 x^{2} - 4 x + 6 x - 8 + 7

Add similar elements:

- 4 x + 6 x = 2 x

= 6 x^{3} + 10 x^{2} + 2 x - 8 + 7

Add the numbers:

- 8 + 7 = - 1

= 6 x^{3} + 10 x^{2} + 2 x - 1

72 + 98

- q^{2} - 9 q - 14

3 x^{10} + 6 x^{8} + 9 x^{6}

\frac{2}{1 - 5}

4 + \frac{1}{5}

What is (3x^2-2)(2x+4)-2x^2+6x+7 ?
The solution to (3x^2-2)(2x+4)-2x^2+6x+7 is 6x^3+10x^2+2x-1