What is expand 3x(x^2-2x+1)(x-1)(x+1) ?

The solution to expand 3x(x^2-2x+1)(x-1)(x+1) is 3x^5-6x^4+6x^2-3x

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expand 3x(x^2-2x+1)(x-1)(x+1)

expand

3 x (x^{2} - 2 x + 1) (x - 1) (x + 1)

3 x^{5} - 6 x^{4} + 6 x^{2} - 3 x

Solution steps

3 x (x^{2} - 2 x + 1) (x - 1) (x + 1)

Expand

3 x (x^{2} - 2 x + 1) (x - 1) (x + 1) : 3 x (x^{2} - 2 x + 1) (x^{2} - 1)

= 3 x (x^{2} - 2 x + 1) (x^{2} - 1)

Expand

3 x (x^{2} - 1) : 3 x^{3} - 3 x

= (3 x^{3} - 3 x) (x^{2} - 2 x + 1)

Distribute parentheses

= 3 x^{3} x^{2} + 3 x^{3} (- 2 x) + 3 x^{3} \cdot 1 - 3 x x^{2} - 3 x (- 2 x) - 3 x \cdot 1

Simplify

3 x^{3} x^{2} + 3 x^{3} (- 2 x) + 3 x^{3} \cdot 1 - 3 x x^{2} - 3 x (- 2 x) - 3 x \cdot 1 : 3 x^{5} - 6 x^{4} + 6 x^{2} - 3 x

= 3 x^{5} - 6 x^{4} + 6 x^{2} - 3 x

28 - 7

(a + 2 b)^{5}

3 \cdot (- 10)

(u + 7)^{2}

π (0.5)^{2}

What is expand 3x(x^2-2x+1)(x-1)(x+1) ?
The solution to expand 3x(x^2-2x+1)(x-1)(x+1) is 3x^5-6x^4+6x^2-3x