What is factor 4m^2+12mn+9n^2-25 ?

The solution to factor 4m^2+12mn+9n^2-25 is (2m+3n+5)(2m+3n-5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

factor 4m^2+12mn+9n^2-25

factor

4 m^{2} + 12 mn + 9 n^{2} - 25

(2 m + 3 n + 5) (2 m + 3 n - 5)

Solution steps

4 m^{2} + 12 mn + 9 n^{2} - 25

Factor

4 m^{2} + 12 mn + 9 n^{2} : (2 m + 3 n)^{2}

= (2 m + 3 n)^{2} - 25

Factor the number:

25 = 5^{2}

= (2 m + 3 n)^{2} - 5^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(2 m + 3 n)^{2} - 5^{2} = ((2 m + 3 n) + 5) ((2 m + 3 n) - 5)

= ((2 m + 3 n) + 5) ((2 m + 3 n) - 5)

Remove parentheses:

(a) = a

= (2 m + 3 n + 5) (2 m + 3 n - 5)

(5 + 2 n)^{3}

k + 1 - 4 (2 k - 9)

2 x (a - 1) - a + 1

- 4 - 15

- 4 - 9 i

What is factor 4m^2+12mn+9n^2-25 ?
The solution to factor 4m^2+12mn+9n^2-25 is (2m+3n+5)(2m+3n-5)