What is (-3+2i)-(4-4i) ?

The solution to (-3+2i)-(4-4i) is -7+6i

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simplify (-3+2i)-(4-4i)

simplify

(- 3 + 2 i) - (4 - 4 i)

- 7 + 6 i

Solution steps

(- 3 + 2 i) - (4 - 4 i)

Group the real part and the imaginary part of the complex number

(a + bi) - (c + d i) = (a - c) + (b - d) i

= (- 3 - 4) + (2 - (- 4)) i

Simplify

(- 3 - 4) + (2 - (- 4)) i : - 7 + 6 i

= - 7 + 6 i

2 \div \frac{4}{3}

i^{2666}

\frac{1}{\frac{1}{a}}

5.301 \cdot 1 0^{7}

sin (θ) + sin (θ)