The solution to (4+i)/(8i) is 1/8-1/2 i

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simplify (4+i)/(8i)

Solution

simplify

\frac{4 + i}{8 i}

\frac{1}{8} - \frac{1}{2} i

Solution steps

\frac{4 + i}{8 i}

Multiply by the conjugate

\frac{- i}{- i}

= \frac{( 4 + i ) ( - i )}{8 i ( - i )}

Simplify

\frac{( 4 + i ) ( - i )}{8 i ( - i )} : \frac{- 4 i + 1}{8}

= \frac{- 4 i + 1}{8}

Rewrite

- 4 i + 1

in standard complex form:

1 - 4 i

= \frac{1 - 4 i}{8}

Apply the fraction rule:

\frac{a + bi}{c} = \frac{a}{c} + \frac{b}{c} i

= \frac{1}{8} + \frac{- 4}{8} i

Cancel

\frac{- 4}{8} : - \frac{1}{2}

= \frac{1}{8} - \frac{1}{2} i

(3 x - 6) (7 x + 7)

15 \cdot 21

\frac{48}{24}

6 x^{5} - 4 x^{4} - 6 x + 4

2 \frac{2}{5} - \frac{6}{5}