What is (4+3i)(4+2i)-(2+i)(3-4i) ?

The solution to (4+3i)(4+2i)-(2+i)(3-4i) is 25i

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simplify (4+3i)(4+2i)-(2+i)(3-4i)

simplify

(4 + 3 i) (4 + 2 i) - (2 + i) (3 - 4 i)

25 i

Solution steps

(4 + 3 i) (4 + 2 i) - (2 + i) (3 - 4 i)

(4 + 3 i) (4 + 2 i) = 10 + 20 i

(2 + i) (3 - 4 i) = 10 - 5 i

= 10 + 20 i - (10 - 5 i)

Expand

- (10 - 5 i) : - 10 + 5 i

= 10 + 20 i - 10 + 5 i

Group like terms

= 20 i + 5 i + 10 - 10

Add similar elements:

20 i + 5 i = 25 i

= 25 i + 10 - 10

Subtract the numbers:

10 - 10 = 0

= 25 i

- 0.8 (- a - 1) + 0.3 a

- 2 x^{2} - 5

x^{3} + 6 x^{2} - 15 x - 90

(- 4) (4)

4 x^{2} + 4 y^{2}

What is (4+3i)(4+2i)-(2+i)(3-4i) ?
The solution to (4+3i)(4+2i)-(2+i)(3-4i) is 25i