What is (x^2-2x-3)/(x^2-9) ?

The solution to (x^2-2x-3)/(x^2-9) is (x+1)/(x+3)

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simplify (x^2-2x-3)/(x^2-9)

simplify

\frac{x ^{2} - 2 x - 3}{x ^{2} - 9}

\frac{x + 1}{x + 3}

Solution steps

\frac{x ^{2} - 2 x - 3}{x ^{2} - 9}

Factor

x^{2} - 2 x - 3 : (x + 1) (x - 3)

= \frac{( x + 1 ) ( x - 3 )}{x ^{2} - 9}

Factor

x^{2} - 9 : (x + 3) (x - 3)

= \frac{( x + 1 ) ( x - 3 )}{( x + 3 ) ( x - 3 )}

Cancel the common factor:

x - 3

= \frac{x + 1}{x + 3}

(- \frac{1}{8})^{2}

- \frac{1}{3} + \frac{1}{24}

\frac{x ^{2} + 16 x + 64}{x ^{2} - 64}

(5 y)^{2} + 13 (5 y) + 42

6 (9 a - 3 b) - 8 (2 a + 4 b)