What are the solutions to the equation -5x^2+7x+2=0 ?

The solutions to the equation -5x^2+7x+2=0 are x=-(-7+sqrt(89))/(10),x=(7+sqrt(89))/(10)

Find the zeros of -5x^2+7x+2=0

The zeros of -5x^2+7x+2=0 are x=-(-7+sqrt(89))/(10),x=(7+sqrt(89))/(10)

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- 5 x^{2} + 7 x + 2 = 0

x = - \frac{- 7 + 89}{10}, x = \frac{7 + 89}{10}

Decimal Notation

x = - 0.24339 \dots, x = 1.64339 \dots

Solution steps

- 5 x^{2} + 7 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 ( - 5 ) \cdot 2}{2 ( - 5 )}

7^{2} - 4 (- 5) \cdot 2 = 89

x_{1, 2} = \frac{- 7 \pm 89}{2 ( - 5 )}

Separate the solutions

x_{1} = \frac{- 7 + 89}{2 ( - 5 )}, x_{2} = \frac{- 7 - 89}{2 ( - 5 )}

x = \frac{- 7 + 89}{2 ( - 5 )} : - \frac{- 7 + 89}{10}

x = \frac{- 7 - 89}{2 ( - 5 )} : \frac{7 + 89}{10}

The solutions to the quadratic equation are:

x = - \frac{- 7 + 89}{10}, x = \frac{7 + 89}{10}

(3^{2})^{\frac{3}{2}}

\frac{3}{8}

20 x^{2} - 13 x - 15 = 0

\frac{w}{5} \leq 4

3 x^{2} < 0

What are the solutions to the equation -5x^2+7x+2=0 ?
The solutions to the equation -5x^2+7x+2=0 are x=-(-7+sqrt(89))/(10),x=(7+sqrt(89))/(10)
Find the zeros of -5x^2+7x+2=0
The zeros of -5x^2+7x+2=0 are x=-(-7+sqrt(89))/(10),x=(7+sqrt(89))/(10)