What are the solutions to the equation x^2+2x=-1 ?

The solutions to the equation x^2+2x=-1 are x=-1

Find the zeros of x^2+2x=-1

The zeros of x^2+2x=-1 are x=-1

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x^{2} + 2 x = - 1

x = - 1

Solution steps

x^{2} + 2 x = - 1

Move

1

to the left side

x^{2} + 2 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot 1 = 0

x_{1, 2} = \frac{- 2 \pm 0}{2 \cdot 1}

x = \frac{- 2}{2 \cdot 1}

\frac{- 2}{2 \cdot 1} = - 1

x = - 1

The solution to the quadratic equation is:

x = - 1

\frac{3}{5} (x - 5) + \frac{2}{3} (x - 3) > - 6

1.98 = 0.044 \cdot n

\frac{n}{4} = 6

2 - x^{2} = - x

- 5 x - 2 x = - 7 x + 1

What are the solutions to the equation x^2+2x=-1 ?
The solutions to the equation x^2+2x=-1 are x=-1
Find the zeros of x^2+2x=-1
The zeros of x^2+2x=-1 are x=-1