What is (2(n^2)^{-5})/(6vn^{-3)} ?

The solution to (2(n^2)^{-5})/(6vn^{-3)} is 1/(3n^7v)

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simplify (2(n^2)^{-5})/(6vn^{-3)}

simplify

\frac{2 ( n ^{2} ) ^{- 5}}{6 v n ^{- 3}}

\frac{1}{3 n ^{7} v}

Solution steps

\frac{2 ( n ^{2} ) ^{- 5}}{6 v n ^{- 3}}

Simplify

(n^{2})^{- 5} : \frac{1}{n ^{10}}

= \frac{2 \cdot \frac{1}{n ^{10}}}{6 v n ^{- 3}}

Factor the number:

6 = 2 \cdot 3

= \frac{2 \cdot \frac{1}{n ^{10}}}{2 \cdot 3 v n ^{- 3}}

Cancel the common factor:

2

= \frac{\frac{1}{n ^{10}}}{3 v n ^{- 3}}

Simplify

\frac{\frac{1}{n ^{10}}}{3 v n ^{- 3}} : \frac{1}{n ^{7} \cdot 3 v}

= \frac{1}{n ^{7} \cdot 3 v}

= \frac{1}{3 n ^{7} v}

4 \div \frac{1}{8}

(- 6) (6) (4) (- 4)

4 (x - 4)^{2}

63 + 420 - 7

8 x - 14

What is (2(n^2)^{-5})/(6vn^{-3)} ?
The solution to (2(n^2)^{-5})/(6vn^{-3)} is 1/(3n^7v)