What are the solutions to the equation 4x^2-48=0 ?

The solutions to the equation 4x^2-48=0 are x=2sqrt(3),x=-2sqrt(3)

Find the zeros of 4x^2-48=0

The zeros of 4x^2-48=0 are x=2sqrt(3),x=-2sqrt(3)

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4 x^{2} - 48 = 0

x = 23, x = - 23

Decimal Notation

x = 3.46410 \dots, x = - 3.46410 \dots

Solution steps

4 x^{2} - 48 = 0

Move

48

to the right side

4 x^{2} = 48

Divide both sides by

4

x^{2} = 12

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 12, x = - 12

12 = 23

- 12 = - 23

x = 23, x = - 23

(64 x^{- 12} y^{- 6})^{- \frac{1}{2}}

c^{2} - 9 c d + 18 d^{2}

32 \cdot 2

2 x^{2} - 2 x - 180 = 0

- 2 (3) + 4 (5) > 5

What are the solutions to the equation 4x^2-48=0 ?
The solutions to the equation 4x^2-48=0 are x=2sqrt(3),x=-2sqrt(3)
Find the zeros of 4x^2-48=0
The zeros of 4x^2-48=0 are x=2sqrt(3),x=-2sqrt(3)