What is factor 4x^2+4x-35 ?

The solution to factor 4x^2+4x-35 is (2x-5)(2x+7)

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factor 4x^2+4x-35

factor

4 x^{2} + 4 x - 35

(2 x - 5) (2 x + 7)

Solution steps

4 x^{2} + 4 x - 35

Break the expression into groups

= (4 x^{2} - 10 x) + (14 x - 35)

Factor out

2 x

from

4 x^{2} - 10 x : 2 x (2 x - 5)

Factor out

7

from

14 x - 35 : 7 (2 x - 5)

= 2 x (2 x - 5) + 7 (2 x - 5)

Factor out common term

2 x - 5

= (2 x - 5) (2 x + 7)

2 x^{2} + 39 = - 18 x

\frac{10 i}{3 + i}

- x^{2} + 8 x - 15 = 0

x > - 2 and x < 11

e^{x} - 2 < 0