What is m^2-n^2+4+4m-1-2n ?

The solution to m^2-n^2+4+4m-1-2n is m^2+4m-n^2-2n+3

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simplify m^2-n^2+4+4m-1-2n

simplify

m^{2} - n^{2} + 4 + 4 m - 1 - 2 n

m^{2} + 4 m - n^{2} - 2 n + 3

Solution steps

m^{2} - n^{2} + 4 + 4 m - 1 - 2 n

Group like terms

= m^{2} + 4 m - n^{2} - 2 n + 4 - 1

Subtract the numbers:

4 - 1 = 3

= m^{2} + 4 m - n^{2} - 2 n + 3

3 (x + 5)^{2}

- 2 [9 - (x + 7)]

\frac{90}{150}

3294

What is m^2-n^2+4+4m-1-2n ?
The solution to m^2-n^2+4+4m-1-2n is m^2+4m-n^2-2n+3